find 'a' if the division of ax^3+9x^2+4x-10 by x+3
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1
Step-by-step explanation:
Let f(x) = ax3 + 9x2 + 4x – 10 by x + 3 x + 3 = 0 ⇒ x = −3 On dividing f(x) by x + 3, it leaves a remainder 5.
Answered by
4
Answer:
left f(x) = ax3 + 9x2 + 4x - 10
x + 3 = 0
x = -3
On dividing f(x) by x+3 it leaves a remainder 5
f (-3) = 5
a (-3)cube + 9(-3) square + 4(-3) - 10 = 5
-27a + 81 - 12 - 10 = 5
54 = 27a
a = 2
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