Question

find 'a' if the division of ax^3+9x^2+4x-10 by x+3​

Answer 1

Step-by-step explanation:

Let f(x) = ax3 + 9x2 + 4x – 10 by x + 3 x + 3 = 0 ⇒ x = −3 On dividing f(x) by x + 3, it leaves a remainder 5.

Answer 2

Answer:

left f(x) = ax3 + 9x2 + 4x - 10

x + 3 = 0

x = -3

On dividing f(x) by x+3 it leaves a remainder 5

f (-3) = 5

a (-3)cube + 9(-3) square + 4(-3) - 10 = 5

-27a + 81 - 12 - 10 = 5

54 = 27a

a = 2