Question

Find a if the equation (5a+1)x²-8ax+3a=0 has equal roots.​

Answer 1

Answer:

a=5a 1,b=-3a, c=3a.They can hav equal root if b^2=4ac,

(-3a)^2=4*3a*(5a 1),

9a^2=12a(5a 1),

9a^2=60a^2 12a,

-51a^2=12a,

a=12a/-51a,

a=-4/17.

I hope this helps please mark brainliest and enjoy your weekend!

Answer 2

Answer:

Required value of a is

Step-by-step explanation:

Given equation,

$(5a + 1) {x}^{2} - 8ax + 3a = 0.......(1)$

We are comparing equation (1) with the equation

$p {x}^{2} + qx + r = 0$

Then get,

$p = 5a + 1 \\ q = - 8a \\ r = 3a$

It is given equation (1) has equal roots.

We know if

$p {x}^{2} + qx + r = 0$

has equal roots then

${q}^{2} - 4pr = 0$

So we are putting value of p,q and r

${(5a + 1)}^{2} - 4 \times ( - 8a) \times (3a) = 0 \\ 25 {a}^{2} + 10a + 1 + 96 {a}^{2} = 0 \\ 121 {a}^{2} + 10a + 1 = 0 \\ 121 {a}^{2} +$