Find a if the line 3x + ay = 8, passes through the intersection of lines represented by
equations 3x – 2y = 10 and 5x + y = 8.
Answers
Answered by
47
Answer:
a=-1
Step-by-step explanation:
3x-2y=10_(1)
5x+y=8
y=8-5x
put the value of y in1 we get
x=2
y= -2
put the value of x and y in eq
3x+ay=8 we get
a=-1
Answered by
23
The value of a is equal to -1.
Given in the question that the line 3x + ay = 8 passes through the point of intersection of the two lines 3x – 2y = 10 and 5x + y = 8 .
Solving the lines 3x – 2y = 10 and 5x + y = 8 for the point of intersection -
5x + y = 8
=> y = 8-5x
3x - 2y = 10
=> 3x - 2(8-5x) = 10 {y = 8-5x}
=> 3x - 16 + 10x = 10
=> 13x = 26
=> x = 2
y = -2
The line 3x + ay = 8 passes through the point (2,-2) and this point will satisfy the line-
=> 6 - 2a = 8
=> a = -1
The value of a which satisfies the equation is -1.
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