Question

Find a if the linear equation 3x-ay has one solution as (4,3)

Answer 1

x=4

y=3

3x-ay=0

3×4-3a=0

12-3a=0

-3a=-12

a=-12/-3

a=4

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Answer 2

$heya \\ \\ \\ \\ 3x - ay = 0 \\ \\ \\ x = 4 \: \: \: \: and \: \: \: \: \: y = 3 \\ \\ \\ \\ 3(4) - a(3) = 0 \\ \\ \\ \\ \\ 3a = 12 \\ \\ \\ \\ a = 4$