Find 'a' if the remainder is 'a' when x3+3x2-ax+3 is divided by x-2
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Step-by-step explanation:
put x-2=0
x=2
now,
p(2)=(2)³+3(2)²-a×2+3
= -8+12-2a+3
= 7-2a
according to question,
p(2)=a
7-2a=a
7=3a
7/3=a
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