Question

find A if x-3 is a factor of
$2 {x}^{3} - 4ax + a$
​

Answer 1

Step-by-step explanation:

x-3=0

x=3

#

$p(x) = 2 {x}^{3} - 4ax + a$

$p(3) = 2 {3}^{3} - 4a(3) + a = 0$

$0 = 2 \times 27 - 12a + a$

$0 = 54 - 11a$

$11a = 54$

$a = \frac{54}{11}$