Question

find'a' if (x-a) is a factor of x³-ax²+2x+a-1

Answer 1

Step-by-step explanation:

6x-9y+33=0

Put the value of Y in the equation i.e 3.

Now,

6x-9(3)+33=0

6x-27+33=0

6x-6=0

6x=6

x=6/6

x=1

So, the value of a = 1

Answer 2

g(x) = x-a = 0

therefore, x = a

p(x) = x³-ax²+2x+a-1

therefore, p(a) = a^3 - a^2 * a + 2a + a -1 =0

(since x-a is a factor of p(x), remainder=0)

=> 3a - 1 = 0

therefore, a = 1/3

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Hope it is helpful!