find a if (x-a) is a factor of x³-ax²+2x+a-5
Answers
Answered by
1
Answer:
3/5
Step-by-step explanation:
as (x-a) is a factor of x³-ax²+2x+a-5=0
substitute x =a in x³-ax²+2x+a-5=0
===> a³-a³+2a+a-5=0
==>3a=5
==>a=3/5
Answered by
0
Answer:
x-a=0
x=a
put the value of x in this equation
x^3-ax^2+2x+a-5
(a)3 -a(a)2 +2×a +a -5
a^3 -a×a^2 +2a +a -5
a^3 -a^3 + 3a - 5. [a^3 - a^3 = 0]
3a - 5=0
3a=5
a=5/3
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