Question

find A in following trignometric equations:- sin²45°=sin(90°-A)

Answer 1

Here is your answer

sin45° = 1/✓2

Sin² 45° = sin(90-A)
(1/✓2)² = Sin(90°-A)
1/2 = Sin(90°-A)
Sin30° = sin(90-A)
90°-A = 30
a = 90°-30°
a = 60°

Hope it helps you ^_^

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Answer 2

Here is your solution :

=> sin²45° = sin( 90° - A )

=> ( sin 45° )² = sin( 90° - A )

=> ( 1/√2 )² = sin( 90° - A )

=> ( 1/2 ) = sin( 90° - A )

Using formula ,

=> sin 30° = ( 1/2 )

=> sin 30° = sin( 90° - A )

As the trigonometric ratios of angles are unique,

So,

=> 30° = 90° - A

=> A = 90° - 30°

•°• A = 60°

Hope it helps !!