Question

find a in the diagram when m1 and m2 are tied to a pully
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Answer 1

Explanation:

To Find -

• acceleration, when m1 and m2 are tied to a pully.

Now,

In m1 :-

$\mathsf{T - m_{1}cos \theta_{1} = m_{1}a \: .....(i)}$

And

In m2 :-

$\mathsf{m_{2}cos \theta_{2} - T = m_{2}a \: .....(ii)}$

Now,

Adding (i) and (ii), we get :-

$\mathsf{m_{2}gcos \theta_{2} - m_{1}gcos \theta_{1} = m_{1}a + m_{2}a}$

$\mathsf{m_{2}gcos \theta_{2} - m_{1}gcos \theta_{1} =a(m_{1} + m_{2})}$

Hence,

$\mathsf {a = \dfrac{m_{2}gcos \theta_{2} - m_{1}gcos \theta_{1} }{m_{1} + m_{2}} }$

Diagram :-

( Refer to the attachment. )

Answer 2

Answer:

OK Ye Chalega Kya.....