find a in the equation when ax^3+3x^2+4x-10 is divided by x-3 and remainder =5
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Answer:
The value of a = - 24/27
Step-by-step explanation:
The given polynomial is divided by x-3 (using long division method)
the remainder left is 27a + 29 = 5 we get a = -24/27.
Aliter:Using factor theorem we can say that x - 3 = 0 and from here we say that x = 3.Put this x = 3 in the given polynomial we get
27a + 29.Equate this equation with 5 we get a = -24/27
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