Question

find a least number which divided by 6 15 12 leave a reminder in each case​

Answer 1

Answer:

To find the least number that when divided by 6, 15, and 18 leaves a remainder 5, we must first find the L.C.M. of 6, 15, and 18 and then add 5.

Find the L.C.M of 6, 15, and 18

6 = 2 × 3

15 = 3 × 5

18 = 2 × 3 × 3

L.C.M of 6, 15 and 18 = 2 x 3 x 3 x 5

L.C.M (6, 15 and 18) = 90

Therefore, the required number = 90+5 = 95

As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.

Answer 2

Answer:

To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number.

L.C.M. of 6, 5 and 18

6 = 2*3

15=3*5

18 = 2*3*3

L.C.M. of 6, 15 and 18 = 2*3*3*5 = 90

Now,

5 +90 = 95

Hence, 95 is the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case.

Let us check our answer.

1) 95/6

Quotient = 15 Remainder = 5

2) 95/15

Quotient = 6 Remainder = 5

3) 95/18

Quotient = 5 Remainder = 5

So. the required number is 95.

Step-by-step explanation:

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