Question

find a least number which when divided by 20,25,35 and 40 leaves remainder as 14 , 19, 29 and 34 respectively

Answer 1

 First find out the LCM of 20,25,35 and 40 

20=2×2×5 

25=5×5 

35=1×5×7 

40=2×`2×2×5 


LCM of 20,25,35 & 40 = 2×2×5×5×7×2=1400 
 
when divided by 20,25,35,40 leaves a remainder 14,19,29,34 
i.e 6 less than the divisor in each case 

Hence the required number =1400−6=1394

Answer 2

Answer:

Step-by-step explanation:

(20-14)=6, (25-19)=6, (35-29)=6, (40-34)=6

Therefore, required number=(LCM of 20,25,35,40)-6 =1394