find a least positive integer which if diminished by 5 is exactly divisible by 36 and 54
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L.C.M of 36,54
36= 2^2 * 3^2
54 = 2 * 3^3
L.C.M = 2^2 * 3^3 = 4*27 = 108
113-5 =108 which is divisible by 36 & 53
hence 113 is the least positive integer which is divisible by 36 and 54 if diminished by 5.
Hope it helps
36= 2^2 * 3^2
54 = 2 * 3^3
L.C.M = 2^2 * 3^3 = 4*27 = 108
113-5 =108 which is divisible by 36 & 53
hence 113 is the least positive integer which is divisible by 36 and 54 if diminished by 5.
Hope it helps
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