Question

find a list of 5 numbers with a mean that is larger than all but one of the Numbers​

Answer 1

Answer:

fjfjrjfjdjrjfjdjjcjdjcjdjfjfjfjdhcudjfjcu

Answer 2

Answer:

1,2,3,4,15

Step-by-step explanation:

Let us consider 5 numbers,

x, x+1,x+2,x+3,x+y

Here , x+y is the only number which is greater than the mean so we don't know how large it is. So we consider it as larger by a number y.

x+y > Mean

Mean > all other numbers(x,x+1,x+2,x+3)

So, Mean should be more than x+3 (first 4 numbers where x+3 is largest)

Mean > x+3

So lets consider the number after x+3 as mean which will be (x+3)+1=x+4

Therefore ,

Mean =x+4

Now taking mean of list of numbers,

(x+x+1+x+2+x+3+x+y)/5=x+4

(5x+6+y )/5 =x+4

5x + 6 +y = 5x +20

6+y = 20

y= 20-6

y=14

So the list of 5 number is

X,x+1,x+2,x+3,x+14

If x=1,

1,2,3,4,15