Question

Find a natural number which is when multiplied by 8 and raise up by 5, it gives out 53. Find the natural number.​

Answer 1

Given:-

$\sf{⟶}$ A natural number which is when multiplied by 8 and raise up by 5, it gives out 53.

To find:-

$\sf{⟶}$ The natural number.

Solution:-

$\sf{⟶}$ Let the natural number be x.

★ It is given that, a natural number (x) when multiplied by 8 and raise up by 5, it gives out 53.

∴ $\sf{8x + 5 = 53}$

Solving the equation

$\sf{⟶}$ $\sf{8x = 53 - 5}$

$\sf{⟶}$ $\sf{8x = 48}$

$\sf{⟶}$ $\sf{x =\dfrac{48}{8}}$

$\sf{⟶}$ $\sf{x = 6}$

Hence, the required natural number is 6.

Answer 2

$\underline{\underline{\orange{\mathcal{Given}}}}$

• A natural number, when multiplied by 8 and raise up by 5, it gives out 53.

$\underline{\underline{\orange{\mathcal{To\: find}}}}$

• The required natural number

$\underline{\underline{\orange{\mathcal{Solution}}}}$

• Let the natural number be x.

$\tt\longmapsto{}$ As per given information in the question, we will make an equation.

★ Equation

$\tt:\implies\: \: \: \: \: \: \: \: {8x + 5 = 53}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {8x = 53 - 5}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {8x = 48}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {x = \dfrac{48}{8}}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {x = 8}$

⠀

$\sf\longmapsto{The\: required\: natural\: number\: is\: 8}$

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