Find a natural number whose square diminished by 84 is equal to thrice of 8 more than the given number.
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Hi ,
Let the natural number = x
Square of the number = x²
According to the problem given,
x² - 84 = 3 ( x + 8 )
x² - 84 = 3x + 24
x ² - 3x -84 - 24 = 0
x² - 3x - 108 = 0
Splitting the middle term
x² - 12x + 9x - 108 = 0
x ( x - 12 ) + 9 ( x - 12 ) = 0
( x - 12 ) ( x + 9 ) = 0
Therefore ,
x - 12 = 0 or x + 9 = 0
x = 12 or x = -9
But x is a natural number ,
Therefore ,
Required natural number = x = 12
I hope this helps you.
:)
Let the natural number = x
Square of the number = x²
According to the problem given,
x² - 84 = 3 ( x + 8 )
x² - 84 = 3x + 24
x ² - 3x -84 - 24 = 0
x² - 3x - 108 = 0
Splitting the middle term
x² - 12x + 9x - 108 = 0
x ( x - 12 ) + 9 ( x - 12 ) = 0
( x - 12 ) ( x + 9 ) = 0
Therefore ,
x - 12 = 0 or x + 9 = 0
x = 12 or x = -9
But x is a natural number ,
Therefore ,
Required natural number = x = 12
I hope this helps you.
:)
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