find a natural number whose square dimnished by 84 is equal to thrice of 8 more than the given number
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according to question ,,, let's take x as number,,
now given
x2-84=3(x+8)
x2 -84= 3x+24
x2-3x-108=0
x2-12x+9x-108=0
x(x-12) +9(x-12)=0
(x+9)(x-12)=0
X(number)= 12
now given
x2-84=3(x+8)
x2 -84= 3x+24
x2-3x-108=0
x2-12x+9x-108=0
x(x-12) +9(x-12)=0
(x+9)(x-12)=0
X(number)= 12
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