Math, asked by komalaru06, 7 months ago

find a nature of solutions of following pair of linear equations 2x-4y=5and 4x-8y=-10​

Answers

Answered by sarbani30
0

Here,

a1 = 2, b1 = -4, c1 = 5

a2 = 4, b2 = -8, c2 = -10

Now,

a1/a2 = 2/4 = 1/2

b1/b2 = -4/-8 = 1/2

c1/c2 = 5/-10 = -1/2

a1/a2 = b1/b2 ≠ c1/c2

The lines are parallel.

They have no solution.

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