Question

Find a no. Which when multiplied by 8 and then redduced by 9 is equal to 47

Answer 1

Given:-

• A number which when multiplied by 8 and then reduced by 9 is equal to 47.

⠀

To find:-

• The number.

⠀

Solution:-

Let,

• the number be x.

⠀

According to the question

→ 8 × x - 9 = 47

→ 8x - 9 = 47

→ 8x = 47 + 9

→ 8x = 56

→ x = 56/8

→ x = 7

⠀

Hence,

• the number is 7.

Answer 2

AnswEr-:

• $\boxed{\sf{\red{ The\:number\:is\: 7}}}$

Explanation-:

• $\mathrm{Given-:}$

• A number is multiplied by 8 and then redduced by 9 is equal to 47.

• $\mathrm{To\:Find\:-:}$

• The numbers.

$\dag{\underline {\mathrm {Solution \:for\:question \:-:}}}$

$\mathrm{Let's\:Assume-:}$

• The number be a .

• $\underbrace {\mathrm {Understanding \:the\:Concept-:}}$

• A number is multiplied by 8 and then redduced by 9 is equal to 47.

• $\longrightarrow{\sf{ New \:Equation \:Formed \:-:x \times 8 - 9 = 47}}$

$\mathrm{Now,\:Solving\:for\:x\:in\:formed\:Equation-:\:}$

• $\longrightarrow{\sf{ \:Equation \: \:-:x \times 8 - 9 = 47}}$

• $\longrightarrow{\sf{ \: \: \:x \times 8 - 9 = 47}}$

• $\longrightarrow{\sf{ 8x - 9 = 47}}$

• $\longrightarrow{\sf{ 8x = 47+ 9}}$

• $\longrightarrow{\sf{ 8x = 56}}$

• $\longrightarrow{\sf{ x= \dfrac{56}{8}}}$

• $\longrightarrow{\sf{ x= \dfrac{\cancel {56}}{\cancel {8}}}}$

• $\longrightarrow{\sf{ x = 7}}$

$\mathrm{Therefore \:-:}$

• $\boxed{\sf{\red{ x = 7}}}$

$\mathrm{Putting \:x =7 \:-:}$

• The number is x = 7

$\mathrm{Hence \:-:}$

• $\boxed{\sf{\red{ The\:number\:is\: 7}}}$

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$\huge{\mathrm{Verification ♡\:-:}}$

• $\longrightarrow{\sf{ \:Equation \:Formed \:-:x \times 8 - 9 = 47}}$

• $\mathrm{Here \:-:}$

• $\longrightarrow{\sf{ x = 7}}$

$\mathrm{Now,\:Putting \:\:x=7\:in\:formed\:Equation-:\:}$

• $\longrightarrow{\sf{ \:Equation \: \:-:x \times 8 - 9 = 47}}$
• $\longrightarrow{\sf{ \: \: \:7 \times 8 - 9 = 47}}$

• $\longrightarrow{\sf{ \: \: \:56 - 9 = 47}}$

• $\longrightarrow{\sf{ \: \: \:47 = 47}}$

Therefore,

• $\longrightarrow{\sf{ \: \: LHS\:=RHS}}$

• $\longrightarrow{\sf{ \:Hence,\:Verified!\:}}$

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