Question

Find a number such that if 25, 7 and 1 are added to it, the product of the first and
third results is equal to the square' of the second,
munt ho added to the numerator and the denominator of the fraction
to​

Answer 1

Answer:

Step-by-step explanation:

Let the no. be x

A/q,

=>(x+25)(x+1)=(x+7)^2

=>x^2+x+25x+25=x^2+14x+49

=>x^2+26x+25=x^2+14x+49

=>x^2-x^2+26x-14x=49-25

=>12x=24

x=2

Hence the required no. is 2