find a number such that if 25,7 and 1 are added to it, the product of the first and third results is equal to the square of the second
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Answer:
The number is 2
Step-by-step explanation:
Let the number be x.
When 25 is added to it, result is 25+x.
When 7 is added to it, result is 7+x.
When 1 is added to it, result is 1+x.
According to question,
Product of first and third result=(25+x)(1+x)
Square of second result=(7+x)(7+x)
On solving (25+x)(1+x)=(7+x)(7+x),
we get 2
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