Question

find a number such that if 25,7 and 1 are added to it, the product of the first and third results is equal to the square of the second​

Answer 1

Answer:

The number is 2

Step-by-step explanation:

Let the number be x.

When 25 is added to it, result is 25+x.

When 7 is added to it, result is 7+x.

When 1 is added to it, result is 1+x.

According to question,

Product of first and third result=(25+x)(1+x)

Square of second result=(7+x)(7+x)

On solving (25+x)(1+x)=(7+x)(7+x),

we get 2