Math, asked by resham2, 1 year ago

find a number such that its excess over 50

Answers

Answered by shaikhafsa
1
Best Answer:  n ............ the number 
n-50 ...... excess over 50 
89-n ...... deficit from 89 

The problem says 

n-50 = (89-n) + 11 ............. solve 
2n = 50 + 89 + 11 
2n = 150 
n = 75 

shaikhafsa: your question was incomplete i think so
resham2: find a number such that its excess over 50 may be greater by 11 than its defect from 89
resham2: thank you
resham2: thank u @shaikhafsa
Answered by MahnoorM
0

Answer:75

Step-by-step explanation:

Take number as x

Now they are saying that x is excess over 50

So (x-50)

Next line is saying this number(x-50) is greater by 11 but with which number??

By deficit from 89 as (89-x)

Now,in inequality form

(x-50)>(89-x) By 11

Now converting it in equality form, we should add 11 to the right side because it’s a smaller number and if we increase it by 11, then both will become equal so,

(x-50)=(89-x)+11

By solving you will get 75.

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