find a number such that its excess over 50
Answers
Answered by
1
Best Answer: n ............ the number
n-50 ...... excess over 50
89-n ...... deficit from 89
The problem says
n-50 = (89-n) + 11 ............. solve
2n = 50 + 89 + 11
2n = 150
n = 75
n-50 ...... excess over 50
89-n ...... deficit from 89
The problem says
n-50 = (89-n) + 11 ............. solve
2n = 50 + 89 + 11
2n = 150
n = 75
shaikhafsa:
your question was incomplete i think so
find a number such that its excess over 50 may be greater by 11 than its defect from 89
thank you
thank u @shaikhafsa
Answered by
0
Answer:75
Step-by-step explanation:
Take number as x
Now they are saying that x is excess over 50
So (x-50)
Next line is saying this number(x-50) is greater by 11 but with which number??
By deficit from 89 as (89-x)
Now,in inequality form
(x-50)>(89-x) By 11
Now converting it in equality form, we should add 11 to the right side because it’s a smaller number and if we increase it by 11, then both will become equal so,
(x-50)=(89-x)+11
By solving you will get 75.
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