Math, asked by noor16204, 10 months ago

Find a number such that three-eights of the number minus one half of
it is 14 less than three-fourths of the number.​

Answers

Answered by biligiri
3

Answer:

let x be the number

as per the given conditions,

3x/8 - x/2 = 3x/4 - 14

=> 3x/8 - x/2 - 3x/4 = -14

=> (3x - 4x - 6x)/8 = 14

=> -7x/8 = - 14

=> x = (- 14) * (- 8/7) [ by transposing -7/8 to RHS]

=> x = 16

Answered by itsmama
3

Answer:

16

Step-by-step explanation:

Let the number be x

ATQ,

3/8x-1/2x=3/4x-14

=3/8x-1/2x-3/4x=-14

=(3x×1)+(-1x×4)+(-3x×2)/8

=3x-4x-6x/8=-14

=-7x/8=-14

=-7x=-14×8

=-7x=-112

=x=-112/-7=16

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