Find a number such that three-eights of the number minus one half of
it is 14 less than three-fourths of the number.
Answers
Answered by
3
Answer:
let x be the number
as per the given conditions,
3x/8 - x/2 = 3x/4 - 14
=> 3x/8 - x/2 - 3x/4 = -14
=> (3x - 4x - 6x)/8 = 14
=> -7x/8 = - 14
=> x = (- 14) * (- 8/7) [ by transposing -7/8 to RHS]
=> x = 16
Answered by
3
Answer:
16
Step-by-step explanation:
Let the number be x
ATQ,
3/8x-1/2x=3/4x-14
=3/8x-1/2x-3/4x=-14
=(3x×1)+(-1x×4)+(-3x×2)/8
=3x-4x-6x/8=-14
=-7x/8=-14
=-7x=-14×8
=-7x=-112
=x=-112/-7=16
Similar questions