Question

find a number such that when 15 is subtracted from 7 times the number, the result is 10 more than twice the number

Answer 1

Concept Introduction:

A statement introduced into an argument whose truth value is accepted as true is called an assumption.

Given: When $15$ is subtracted from $7$ times the number, the result is $10$more than twice the number.

To Find: We have to find the number.

Solution:

Let the number be x.

$7x -15 = 2x + 10$

$5x = 25$

$5x = 25$

$x = 5$

Final Answer:

the number must be $5$

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Answer 2

The required number = 5

Given :

A number such that when 15 is subtracted from 7 times the number, the result is 10 more than twice the number

To find :

The number

Solution :

Step 1 of 2 :

Form the equation to find the number

Let the required number = n

When 15 is subtracted from 7 times the number the result is 7n - 15

Also when 10 more than twice the number the result is 2n + 10

By the given condition

$\displaystyle \sf 7n - 15 = 2n + 10$

Step 2 of 2 :

Find the number

$\displaystyle \sf 7n - 15 = 2n + 10$

$\displaystyle \sf{ \implies }7n - 2n = 10 + 15$

$\displaystyle \sf{ \implies }5n = 25$

$\displaystyle \sf{ \implies }n = \frac{25}{5}$

$\displaystyle \sf{ \implies }n = 5$

Hence the required number = 5

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