Math, asked by bthfrk, 11 months ago

find a number twice whose value is equal to 15 more than half its value

Answers

Answered by oliviagunda
3

Answer:

10

Step-by-step explanation:

2x = 15 + x/2

3/2 x = 15

3x = 30

x = 10


srishti31052003: X cannot be 15, it does not satisfy your equation itself
oliviagunda: yes it does
oliviagunda: nevermind sorry
oliviagunda: im going to edit it
srishti31052003: Yup ^_^
Answered by srishti31052003
1

Answer:

Step-by-step explanation:

Let number be =x

Therefore the equation for the question will be:

2x=15+x÷2

2x=30+x÷2

2x*2=30+x

4x=30+x

4x-x=30

3x=30

x=30÷3

x=10

Therefore the number desired is 10

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