find a number which is 28 greater than the average of its one third, quarter and one twelfth
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Step-by-step explanation:
Let the unknown number be 'x'
Let the sum of terms be 'S'
Let the no.of terms be 'n'
Let the average be 'A'
Average=Sum of terms/No.of terms
Sum of terms=One third of x+Quarter of x+One twelfth of x
S=(x/3)+(x/4)+(x/12)
S=(4x+3x+x)/12
S=8x/12
S=2x/3
n=3
A=(2x/3)×(1/3)
A=2x/9
As per the problem, the unknown number is 28 more than average
i.e x=28+(2x/9)
=> x-(2x/9)=28
=> (9x-2x)/9=28
=> 7x/9=28
=> 7x=36
=> x=36
Therefore the required number is 36
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