Find a number which is exactly divisible by 2,3,5,7 and 11. Justify your answer.And if you don't know the answer p,s don't answer as i have very very less points and i couldn't ask questions now. pls.
Answers
Step-by-step explanation:
A divisibility rule is a heuristic for determining whether a positive integer can be evenly divided by another (i.e. there is no remainder left over). For example, determining if a number is even is as simple as checking to see if its last digit is 2, 4, 6, 8 or 0. Multiple divisibility rules applied to the same number in this way can help quickly determine its prime factorization without having to guess at its prime factors.
positive integer
if the last digit of NN is 2, 4, 6, 8, or 0;
3
if the sum of digits of NN is a multiple of 3;
\
4
if the last 2 digits of NN are a multiple of 4;
5
if the last digit of NN is either 0 or 5;
\
6
if NN is divisible by both 2 and 3;
7
if subtracting twice the last digit of NN from the remaining digits gives a multiple of 7 (e.g. 658 is divisible by 7 because 65 - 2 x 8 = 49, which is a multiple of 7);
\
8
if the last 3 digits of NN are a multiple of 8;
9
if the sum of digits of NN is a multiple of 9;
10
if the last digit of NN is 0;
11
if the difference of the alternating sum of digits of NN is a multiple of 11 (e.g. 2343 is divisible by 11 because 2 - 3 + 4 - 3 = 0, which is a multiple of 11);
\color
12
if NN is divisible by both 3 and 4.