Question

find a number which is less than 200 wich is both a perfect square and a perfect cube​

Answer 1

Answer:

1 & 64

Explanation:

${1}^{2} = 1 \: and \: {1}^{3} = 1 \\ {8}^{2} = 64 \: and \: {4}^{3} = 64$

Answer 2

Answer:

Hence 1 and 64 are such numbers which are perfect cube and square and also less than 200

Step-by-step explanation:

In context to questions asked

We have to determine the value of the number which is perfect square and perfect cube and also less than 200

So number which are square and less than 200 are

${1}^{2} = 1 \\ {2}^{2} = 4 \\ {3}^{2} = 9 \\ {4}^{2} = 16 \\ {5}^{2} = 25 \\ {6}^{2} = 36 \\ {7}^{2} = 49 \\ {8}^{2} = 64 \\ {9}^{2} = 81 \\ {10}^{2} = 100 \\ {11}^{2} = 121 \\ {12}^{2} = 144 \\ {13}^{2} = 169 \\ {14}^{2} = 196$

Number which are perfect cube and less than 200 are

${1}^{3} = 1 \\ {2}^{3} = 8 \\ {3}^{3} = 27 \\ {4}^{3} = 64 \\ {5}^{3} = 125$

Hence such numbers are 1 and 64