Question

find a number which is twenty eight greater than the average of its one third, quarter and one twelfth.

Answer 1

Answer:

36

Step-by-step explanation:

step1).

$\frac{1}{3} \times 36 = 12$

step2).

$\frac{1}{4} \times 36 = 9$

step3).

$\frac{1}{12} \times 36 = 3$

step4). 12 + 9 + 3 = 24

step5). average = 24/3 = 8

now, according to question, the number is 36 and it's average is 8 and 36 - 8 = 28. That means, 36 is the number which is 28 greater than the average of its 1/3, 1/4, and 1/12 part.

I hope it will help you! :)