Question

find a number which when multiplied by 7 and then reduced by 3 is equal to 47 .


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Answer 1

r={8}

PREMISES

y=(7r-3=53)

CALCULATIONS

y=(7r-3=53)

7r-3=53

7r/7-(3–3)=(53+3)/7

1r-0=56/7

r=56/7 (Cancel the common factor 7 in the divisor then adjust the numerator)

r=8/1

r=

8

PROOF

If r=8, then the inverse of the mathematical phrase 7r-3 brings

y+3=7r

53+3=7(8) and

56=56 establishes proof of the root (zero) r=8 for the statement 7r-3=53

C.H.