Question

Find a number which when multiplied by 8 and then reduced by 9 is equal to 47.​

Answer 1

Given:

A number which when multiplied by 8 and then reduced by 9 is equal to 47.

To Find:

Number

Solution:

Let that number be = a

Now

According to question:

When number is multiplied by 8 and then reduced by 9 is equal to 47.

So

=> 8×a - 9 = 47

=> 8a - 9 = 47

=> 8a = 56

=> a = 56/8

=> a = 7

Hence, required number is 7.

Answer 2

Given: A number which when multiplied by 8 and then reduced by 9 is equal to 47.

Need to find: The Number.

❒ Let the required number be x.

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$\qquad\boxed{\bf{\mid{\overline{\underline{\purple{\bigstar\: According \; to\;the \; Question \; \: :}}}}}\mid}$

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• When number is multiplied by 8 and reduced by 9 is equal to 47.

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Therefore,

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$:\implies\sf 8 \times x - 9 = 47 \\\\\\:\implies\sf 8x - 9 = 47 \\\\\\:\implies\sf 8x = 47 + 9\\\\\\:\implies\sf 8x = 56\\\\\\:\implies\sf x = \cancel\dfrac{56}{8}\\\\\\:\implies{\underline{\boxed{\frak{\purple{x = 7}}}}}\;\bigstar$

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$\therefore{\underline{\sf{Hence, \: the\; required\; number\:is \; \bf{7}.}}}$