Find a number who double is 45 greater than its half
Answers
Answered by
0
Answer:
30
Step-by-step explanation:
Let x be the required number.
Now the double of a number will be 2x and the half of a number will be x/2
.
Since we are given that a number whose double is 45 greater than its half, so mathematically we can write
2x=x/2+45
By rewriting the equation, we get
⇒2x−x/2=45
Taking LCM on LHS, we get
⇒2x×2/2−x/2=45
By simplifying the equation, we get
⇒4x/2−x/2=45
⇒4x−x/2=45
Subtracting the terms in the denominator, we get
⇒3x2=45
Multiplying both sides by 2, we get
⇒3x=45×2
⇒3x=90
Dividing both sides by 3, we get
⇒x=903
⇒x=30
Answered by
0
Answer:
30
Step-by-step explanation:
Let the number be y
=45+1/2y=2y
=45+0.5y=2y
=45=2y-0.5y
=45=1.5y
=45=3/2y
=3/2y=45
=3y=45x2
=3y=90
=y=90/3
=y=30
Therefore the answer is 30
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