Math, asked by swarupaash75, 4 days ago

Find a number who double is 45 greater than its half ​

Answers

Answered by djshamax
0

Answer:

30

Step-by-step explanation:

Let x  be the required number.

Now the double of a number will be 2x  and the half of a number will be x/2

.

Since we are given that a number whose double is 45 greater than its half, so mathematically we can write

2x=x/2+45

By rewriting the equation, we get

⇒2x−x/2=45

Taking LCM on LHS, we get

⇒2x×2/2−x/2=45

By simplifying the equation, we get

⇒4x/2−x/2=45

⇒4x−x/2=45

Subtracting the terms in the denominator, we get

⇒3x2=45

Multiplying both sides by 2, we get

⇒3x=45×2

⇒3x=90

Dividing both sides by 3, we get

⇒x=903

⇒x=30

Answered by 21sv0056abhiram
0

Answer:

30

Step-by-step explanation:

Let the number be y

=45+1/2y=2y

=45+0.5y=2y

=45=2y-0.5y

=45=1.5y

=45=3/2y

=3/2y=45

=3y=45x2

=3y=90

=y=90/3

=y=30

Therefore the answer is 30

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