Question

find a number whose double is 45 greater than its half

Answer 1

Let the number be xAccording to the question :-2x=45+ x/2 => 2x= (45*2 + x )/2Multiplying both sides by 2=>2* 2x= 90+x=>4x=90+xSubtracting x from both sides=>4x-x=90=>3x=90Dividing both sides by 3=>x=90/3=>x=30Verification:-2x=45+x/22*30=45+30/260=45+1560=60LHS=RHSTherefore, verified...Hence,the number is 30

Answer 2

Hi friends the answer is..
2x = x/2 + 45
==> 2x - x/2 = 45
<==> (3x)/2 = 45
==> 3x = 90
==> x = 90/3 = 30, the unknown number.
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