Question

find a number whose double is 45 greater than its half

Answer 1

Heya!!!

HERE IS THE ANSWER

Let the no. be x

so its double = 2 × x =2x

and its half is x/2

So A/Q

$2x = \frac{x}{2} + 45 \\ 2x - \frac{x}{2} = 45 \\ \frac{4x - x}{2} = 45 \\ \frac{3x}{ 2} = 45 \\ x = \frac{45 \times 2}{3} \\ x = 30$


So the number is 30.

Hope it helps to you.

$= = = = = = = = = =$

Answer 2

HEY YOUR ANSWER IS .....


Let the number = x ,

So ,

2x = x/2 +45

$2x = \frac{x + 90}{2}$
So ,

4x = x + 90

So ,

4x-x=90

So ,

3x = 90

So ,

x = 90/3

So ,

x = 30 .


Therefore , the required number = x = 30 .