find a number whose fifth part increased by 30 is equal to its fourth part decreased by 30
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Let the number = x
Then it is given that
x/5 + 30 = x/4 - 30
Transport -30 from RHS to LHS and x/5 from LHS to RHS
We now have 30+30 = x/4 - x/5
60 = x/20
So x = 60*20
x=1200
Then it is given that
x/5 + 30 = x/4 - 30
Transport -30 from RHS to LHS and x/5 from LHS to RHS
We now have 30+30 = x/4 - x/5
60 = x/20
So x = 60*20
x=1200
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