Question

Find a number whose one third part exceeds its one fifth part by 20

Answer 1

let the no be x
1x/3=1x/5+20
x/3-x/5=20
(5x-3x)/15=20
2x=300
x=150
justification
150/3=50
150/5=30
50=30+20....

Answer 2

Dear Student,

● Answer -

150

◆ Explanation -

Let x be the required number.

Given that x/3 exceeds x/5 by 20. In equation form, this is written as -

x/3 = x/5 + 20

x/3 - x/5 = 20

x (1/3 - 1/5) = 20

x (5/15 - 3/15) = 20

x × 2/15 = 20

x = 20 × 15 / 2

x = 150

Hence, the required number is 150.

Hope this helps you...