Question

find a number whose one-third part exceeds its one - fifth part by 20

Answer 1

Let the no. Be x
Now its one third part is x/3 and one fifth part is x/5
Now x/3 =x/5 +20
(x/3)-(x/5)=20
(5x -3x)/15= 20 ....taking lcm
Now
2x/15=20
2x=(20)(15)
2x=300
X=150
Hope it helps