Find a number whose two-thirds part exceeds Its three-fifths part by 10.
Answers
Answered by
3
Let the number be x
so two fifth part = 2x/3
three fifth part = 3x/5
by the condition given in your question we get equation
2x/3 - 3x /5 = 10
10x - 9x /15 = 10
x /15 = 10
x = 10 × 15
x = 150
so the required number is 50
so two fifth part = 2x/3
three fifth part = 3x/5
by the condition given in your question we get equation
2x/3 - 3x /5 = 10
10x - 9x /15 = 10
x /15 = 10
x = 10 × 15
x = 150
so the required number is 50
Answered by
2
Hey!
Let the number be x.
As per the question,
2/3 of x is 10 greater than 3/5 of x.
2/3*x - 3/5*x = 10.
2x/3 - 3x/5 = 10.
(10x-9x)/15=10.
x= 10*15= 150.
So the number is 150.
Hope it helps.
Let the number be x.
As per the question,
2/3 of x is 10 greater than 3/5 of x.
2/3*x - 3/5*x = 10.
2x/3 - 3x/5 = 10.
(10x-9x)/15=10.
x= 10*15= 150.
So the number is 150.
Hope it helps.
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