Question

Find A.P where a= -3 and b=
$\binom{ - 2}{3}$
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Answer 1

Given:

First term, a = -3

Common Difference, d =

$\binom{ - 2}{3} \: \: i.e = - 0.6$

If we add the d (Common Difference ) in the terms, we automatically get the next term.

Second Term, = ${t}^{2} = - 3+ ( - 0.6) = - 3.6$

Third Term, =${t}^{3} = - 3.6 + ( - 0.6) = - 4.2$

Fourth Term, =${t }^{4} = - 4.2 + ( - 0.6) = - 4.8$

Hence,

A.P formed ―

$- 3, \: - 3.6, \: - 4.2, \: - 4.8,....$

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Answer 2

Answer:

Given:

First term, a = -3

Common Difference, d =

\binom{ - 2}{3} \: \: i.e = - 0.6(

3

−2

)i.e=−0.6

If we add the d (Common Difference ) in the terms, we automatically get the next term.

Second Term, = {t}^{2} = - 3+ ( - 0.6) = - 3.6t

2

=−3+(−0.6)=−3.6

Third Term, ={t}^{3} = - 3.6 + ( - 0.6) = - 4.2t

3

=−3.6+(−0.6)=−4.2

Fourth Term, ={t }^{4} = - 4.2 + ( - 0.6) = - 4.8t

4

=−4.2+(−0.6)=−4.8

Hence,

A.P formed ―

- 3, \: - 3.6, \: - 4.2, \: - 4.8,....−3,−3.6,−4.2,−4.8,...