Question

Find A.P which fifth terms are 5 and common difference is –3. please give me the answer quickly ​

Answer 1

Given, 5th term is 5 and common difference is -3

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5a + 4(-3) = 5

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5a + 4(-3) = 5a -12 = 5

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5a + 4(-3) = 5a -12 = 5a = 17

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5a + 4(-3) = 5a -12 = 5a = 17first term ;

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5a + 4(-3) = 5a -12 = 5a = 17first term ;a = a1 = 17

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5a + 4(-3) = 5a -12 = 5a = 17first term ;a = a1 = 17second term ;

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5a + 4(-3) = 5a -12 = 5a = 17first term ;a = a1 = 17second term ;a2 = a + d = 17 + (-3) = 17-3

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5a + 4(-3) = 5a -12 = 5a = 17first term ;a = a1 = 17second term ;a2 = a + d = 17 + (-3) = 17-3a2 = 14

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5a + 4(-3) = 5a -12 = 5a = 17first term ;a = a1 = 17second term ;a2 = a + d = 17 + (-3) = 17-3a2 = 14third term ;

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5a + 4(-3) = 5a -12 = 5a = 17first term ;a = a1 = 17second term ;a2 = a + d = 17 + (-3) = 17-3a2 = 14third term ;a3 = a + 2d = 17 +2(-3) = 17-6

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5a + 4(-3) = 5a -12 = 5a = 17first term ;a = a1 = 17second term ;a2 = a + d = 17 + (-3) = 17-3a2 = 14third term ;a3 = a + 2d = 17 +2(-3) = 17-6a3 = 11

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5a + 4(-3) = 5a -12 = 5a = 17first term ;a = a1 = 17second term ;a2 = a + d = 17 + (-3) = 17-3a2 = 14third term ;a3 = a + 2d = 17 +2(-3) = 17-6a3 = 11The required AP :

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5a + 4(-3) = 5a -12 = 5a = 17first term ;a = a1 = 17second term ;a2 = a + d = 17 + (-3) = 17-3a2 = 14third term ;a3 = a + 2d = 17 +2(-3) = 17-6a3 = 11The required AP :17,14,11,.....

Given, 5th term is 5 and common difference is -3a5 = a + 4d = 5a + 4(-3) = 5a -12 = 5a = 17first term ;a = a1 = 17second term ;a2 = a + d = 17 + (-3) = 17-3a2 = 14third term ;a3 = a + 2d = 17 +2(-3) = 17-6a3 = 11The required AP :17,14,11,.....Hope it help you.

Answer 2

Answer:

a = 17

Step-by-step explanation:

As it is given that 5th term is 5

we can say that a+4d=5

d is given as -3

a+4(-3)=5

then a=17