Question

find a.p whose first term is 100 and the sum of whose first six terms is 5 times the sum of next 6 terms

Answer 1

girls writing the answer try to try to find by yourself that way you can increase your curiosity Sun and if you don't know another ladies writing so from copy her I know you are copying for exam

Answer 2

a=100
(s6)×5=(s12-s6)
[6/2(2×100+5d)]×5=[12/2(2×100+11d)]-[6/2(200+5d)]
[3(200+5d)]×5=[6(200+11d)]-3(200+5d)
(600+15d)×5=1200+66d-600-15d
3000+75d=600+51d
75d-51d=600-3000
24d=-2400
d=-2400/24=-1000
a2=a+d=100-1000=-900
a3=a+2d=100+2×-1000=100-2000=-1900
Ap=100,-900,-1900