Find a pair of consecutive even integers greater than 5 whose sum is less than 23
Answers
Answered by
74
Hey!
____
____________________________________________________________
Ques. Find a pair of consecutive even integers greater than 5 whose sum is less than 23 .
Ans.→ Let the pairs be denoted by x and ( x + 2 ) since they are even as well as consecutive.
=> According to the Question :-
→ x > 5 ----------- ( Eq. 1 )
→ x + x + 2 < 23
= 2x + 2 < 23
= 2x < 21
=> x < 10.5 -----------( Eq. 2 )
Thus, from the equations we have the condition ,
→5 < x < 10.5
★ Now we need to choose only The positive as well as even consecutive integers lying in this range .
°•° The pairs are ( 6 , 8 ) , ( 8, 10 ) and ( 6 , 10 )
____________________________________________________________
____
____________________________________________________________
Ques. Find a pair of consecutive even integers greater than 5 whose sum is less than 23 .
Ans.→ Let the pairs be denoted by x and ( x + 2 ) since they are even as well as consecutive.
=> According to the Question :-
→ x > 5 ----------- ( Eq. 1 )
→ x + x + 2 < 23
= 2x + 2 < 23
= 2x < 21
=> x < 10.5 -----------( Eq. 2 )
Thus, from the equations we have the condition ,
→5 < x < 10.5
★ Now we need to choose only The positive as well as even consecutive integers lying in this range .
°•° The pairs are ( 6 , 8 ) , ( 8, 10 ) and ( 6 , 10 )
____________________________________________________________
Answered by
0
Hi
Here is the answer
The sum of consecutive five integers whose sum are less than 5 are( 6,8) ,(8,10),(6,10)
Hope it helps
Here is the answer
The sum of consecutive five integers whose sum are less than 5 are( 6,8) ,(8,10),(6,10)
Hope it helps
Similar questions