Question

Find a pair of integers whose product is -36 and whose difference is 15.​

Answer 1

Step-by-step explanation:

There are few pairs of integers whose product is – 15. e.g. – 1 × 15 – 3 × 5 3 × – 5 15 × – 1 but difference of –3 and 5 or –5 and 3 is 8. So the required pair of integers is – 3 5 and – 5 3.

Answer 2

Answer: Let one integer be x and other be y

∴ x × y = -36  __(i)

&  x - y = 15

∴ x = 15 + y __(ii)

Substituting (ii) in (i)

(15 + y) × y = -36

∴ y² + 15y + 36 = 0

∴ y² + 12y + 3y + 36 = 0

∴ y(y + 12) + 3(y + 12) = 0

∴ (y + 3) (y + 12) = 0

∴ y = -3 & y = -12

IF y = -3 then x = 12

IF y = -12 then x = 3

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