Find a pair of integers whose product is -36 and whose difference is 15
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Hey Mate !
Here is your solution :
Let the numbers are x and y.
According to question ,
=> Product of numbers = -36
=> xy = -36 ----------- ( 1 )
And ,
=> Difference of numbers = 15
=> x - y = 15 ------------ ( 2 )
To find the value of x and y , first we need to find the value of ( x + y ).
Now,
=> ( x + y )² = ( x - y )² + 4xy
By substituting the value of ( 1 ) and ( 2 ),
=> ( x + y )² = ( 15 )² + 4 ( -36 )
=> ( x + y )² = 225 - 144
=> ( x + y )² = 81
=> ( x + y ) = √81
=> ( x + y ) = 9 ---------- ( 3 )
By adding ( 1 ) and ( 3 ) ,
=> x + y + x - y = 9 + 15
=> 2x = 24
=> x = 24 ÷ 2
=> x = 12
By substituting x in ( 1 ),
=> x - y = 15
=> 12 - y = 15
=> -y = 15 - 12
=> -y = 3
=> y = -3
Hence , the numbers are 12 and -3.
==============================
Hope it helps !! ^_^
Here is your solution :
Let the numbers are x and y.
According to question ,
=> Product of numbers = -36
=> xy = -36 ----------- ( 1 )
And ,
=> Difference of numbers = 15
=> x - y = 15 ------------ ( 2 )
To find the value of x and y , first we need to find the value of ( x + y ).
Now,
=> ( x + y )² = ( x - y )² + 4xy
By substituting the value of ( 1 ) and ( 2 ),
=> ( x + y )² = ( 15 )² + 4 ( -36 )
=> ( x + y )² = 225 - 144
=> ( x + y )² = 81
=> ( x + y ) = √81
=> ( x + y ) = 9 ---------- ( 3 )
By adding ( 1 ) and ( 3 ) ,
=> x + y + x - y = 9 + 15
=> 2x = 24
=> x = 24 ÷ 2
=> x = 12
By substituting x in ( 1 ),
=> x - y = 15
=> 12 - y = 15
=> -y = 15 - 12
=> -y = 3
=> y = -3
Hence , the numbers are 12 and -3.
==============================
Hope it helps !! ^_^
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