find a pair of integers whose product is -36 and whose differenve is 15
Answers
Answered by
1
Let the pair of integers be a and b.
ab=-36
a-b=15
a=15+b
(15+b)×b=-36
b^2+15b+36=0
b^2+12b+3b+36=0
b (b+12)+3 (b+12)=0
(b+3)(b+12)=0
b=-3 or -12
a=12 or 3
ab=-36
a-b=15
a=15+b
(15+b)×b=-36
b^2+15b+36=0
b^2+12b+3b+36=0
b (b+12)+3 (b+12)=0
(b+3)(b+12)=0
b=-3 or -12
a=12 or 3
Similar questions