Question

find a pair of integers whose product is -36and whose differenve is15

Answer 1

Let numbers are x and (x - 15)

According to the question :

Their product = -36

x(x - 15) = -36

x² - 15x = -36

x² - 15x + 36 = 0

x² - (12 + 3)x + 36 = 0

x² - 12x - 3x + 36 = 0

x(x - 12) - 3(x - 12) = 0

(x - 12)(x - 3) = 0

x = 12 or 3

Required values of x are 12 and 3.



×××××××××××××××
If we take, x = 12
Numbers are, 12 and (12 - 15)=-3

If we take, x = 3
Numbers are, 3 and (3 - 15) = -12


I hope this will help you

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