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Find a pair of numbers whose sum is ♣3♣ and product is ♣- 138♣
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Let the no. Be x and y
X+y=3 y=3- x
x.y=-138
x(3-x)=-138
3x-x² +138=0
x² +3x-138 =0
x² +3x +9÷4 -138=0
(x+3÷2)² =138-9÷4
(2x+3)²÷4 =543÷4
(2x+3)² =543
2x+3=23.30
2x=20.30
x=10.15
y=3-10.15 => - 7.15
X+y=3 y=3- x
x.y=-138
x(3-x)=-138
3x-x² +138=0
x² +3x-138 =0
x² +3x +9÷4 -138=0
(x+3÷2)² =138-9÷4
(2x+3)²÷4 =543÷4
(2x+3)² =543
2x+3=23.30
2x=20.30
x=10.15
y=3-10.15 => - 7.15
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