Find a perimeter of rectangle with digonal 17cm and length of one side is 15cm.
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Answer:
l=length,b=breadth,h=height
h=17
l^2+b^2=h^2
15^2+b^2=17^2
b^2=289-225=64
b=8
perimeter of rectangle=2(l+b)
=2(15+8)
=2(23)
=46
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