Question

find a phythogorean triplet whose largest member is 29

Answer 1

formula of finding Pythagorean  triplet =2m,   [m^2 -1]   and  [m^2 +1]

largest member is 29

ATP

[m^2 +1] =29..............................[3]

m^2=29 - 1 =28

m=√28 =5.29

[m^2 -1] = [5.29]^2 -1 =27.98 -1 =26.98  OR  [m^2 -1] = [√28]^2 -1] =28-1=27.....[2]

⇒2m =2*5.29 =10.58........[1]

Pythagorean  triplets are = [ 10.58,  26.98 ,29]  OR  [10.58, 27 ,29]